Integrand size = 19, antiderivative size = 171 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=-\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}+\frac {16 d (c+d x)^{3/2}}{99 (b c-a d)^2 (a+b x)^{9/2}}-\frac {32 d^2 (c+d x)^{3/2}}{231 (b c-a d)^3 (a+b x)^{7/2}}+\frac {128 d^3 (c+d x)^{3/2}}{1155 (b c-a d)^4 (a+b x)^{5/2}}-\frac {256 d^4 (c+d x)^{3/2}}{3465 (b c-a d)^5 (a+b x)^{3/2}} \]
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Time = 0.03 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {47, 37} \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=-\frac {256 d^4 (c+d x)^{3/2}}{3465 (a+b x)^{3/2} (b c-a d)^5}+\frac {128 d^3 (c+d x)^{3/2}}{1155 (a+b x)^{5/2} (b c-a d)^4}-\frac {32 d^2 (c+d x)^{3/2}}{231 (a+b x)^{7/2} (b c-a d)^3}+\frac {16 d (c+d x)^{3/2}}{99 (a+b x)^{9/2} (b c-a d)^2}-\frac {2 (c+d x)^{3/2}}{11 (a+b x)^{11/2} (b c-a d)} \]
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Rule 37
Rule 47
Rubi steps \begin{align*} \text {integral}& = -\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}-\frac {(8 d) \int \frac {\sqrt {c+d x}}{(a+b x)^{11/2}} \, dx}{11 (b c-a d)} \\ & = -\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}+\frac {16 d (c+d x)^{3/2}}{99 (b c-a d)^2 (a+b x)^{9/2}}+\frac {\left (16 d^2\right ) \int \frac {\sqrt {c+d x}}{(a+b x)^{9/2}} \, dx}{33 (b c-a d)^2} \\ & = -\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}+\frac {16 d (c+d x)^{3/2}}{99 (b c-a d)^2 (a+b x)^{9/2}}-\frac {32 d^2 (c+d x)^{3/2}}{231 (b c-a d)^3 (a+b x)^{7/2}}-\frac {\left (64 d^3\right ) \int \frac {\sqrt {c+d x}}{(a+b x)^{7/2}} \, dx}{231 (b c-a d)^3} \\ & = -\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}+\frac {16 d (c+d x)^{3/2}}{99 (b c-a d)^2 (a+b x)^{9/2}}-\frac {32 d^2 (c+d x)^{3/2}}{231 (b c-a d)^3 (a+b x)^{7/2}}+\frac {128 d^3 (c+d x)^{3/2}}{1155 (b c-a d)^4 (a+b x)^{5/2}}+\frac {\left (128 d^4\right ) \int \frac {\sqrt {c+d x}}{(a+b x)^{5/2}} \, dx}{1155 (b c-a d)^4} \\ & = -\frac {2 (c+d x)^{3/2}}{11 (b c-a d) (a+b x)^{11/2}}+\frac {16 d (c+d x)^{3/2}}{99 (b c-a d)^2 (a+b x)^{9/2}}-\frac {32 d^2 (c+d x)^{3/2}}{231 (b c-a d)^3 (a+b x)^{7/2}}+\frac {128 d^3 (c+d x)^{3/2}}{1155 (b c-a d)^4 (a+b x)^{5/2}}-\frac {256 d^4 (c+d x)^{3/2}}{3465 (b c-a d)^5 (a+b x)^{3/2}} \\ \end{align*}
Time = 0.33 (sec) , antiderivative size = 170, normalized size of antiderivative = 0.99 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=-\frac {2 (c+d x)^{3/2} \left (1155 a^4 d^4+924 a^3 b d^3 (-3 c+2 d x)+198 a^2 b^2 d^2 \left (15 c^2-12 c d x+8 d^2 x^2\right )+44 a b^3 d \left (-35 c^3+30 c^2 d x-24 c d^2 x^2+16 d^3 x^3\right )+b^4 \left (315 c^4-280 c^3 d x+240 c^2 d^2 x^2-192 c d^3 x^3+128 d^4 x^4\right )\right )}{3465 (b c-a d)^5 (a+b x)^{11/2}} \]
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Time = 0.26 (sec) , antiderivative size = 248, normalized size of antiderivative = 1.45
method | result | size |
default | \(-\frac {\sqrt {d x +c}}{5 b \left (b x +a \right )^{\frac {11}{2}}}+\frac {\left (a d -b c \right ) \left (-\frac {2 \sqrt {d x +c}}{11 \left (-a d +b c \right ) \left (b x +a \right )^{\frac {11}{2}}}-\frac {10 d \left (-\frac {2 \sqrt {d x +c}}{9 \left (-a d +b c \right ) \left (b x +a \right )^{\frac {9}{2}}}-\frac {8 d \left (-\frac {2 \sqrt {d x +c}}{7 \left (-a d +b c \right ) \left (b x +a \right )^{\frac {7}{2}}}-\frac {6 d \left (-\frac {2 \sqrt {d x +c}}{5 \left (-a d +b c \right ) \left (b x +a \right )^{\frac {5}{2}}}-\frac {4 d \left (-\frac {2 \sqrt {d x +c}}{3 \left (-a d +b c \right ) \left (b x +a \right )^{\frac {3}{2}}}+\frac {4 d \sqrt {d x +c}}{3 \left (-a d +b c \right )^{2} \sqrt {b x +a}}\right )}{5 \left (-a d +b c \right )}\right )}{7 \left (-a d +b c \right )}\right )}{9 \left (-a d +b c \right )}\right )}{11 \left (-a d +b c \right )}\right )}{10 b}\) | \(248\) |
gosper | \(\frac {2 \left (d x +c \right )^{\frac {3}{2}} \left (128 d^{4} x^{4} b^{4}+704 a \,b^{3} d^{4} x^{3}-192 b^{4} c \,d^{3} x^{3}+1584 a^{2} b^{2} d^{4} x^{2}-1056 a \,b^{3} c \,d^{3} x^{2}+240 b^{4} c^{2} d^{2} x^{2}+1848 a^{3} b \,d^{4} x -2376 a^{2} b^{2} c \,d^{3} x +1320 a \,b^{3} c^{2} d^{2} x -280 b^{4} c^{3} d x +1155 a^{4} d^{4}-2772 a^{3} b c \,d^{3}+2970 a^{2} b^{2} c^{2} d^{2}-1540 a \,b^{3} c^{3} d +315 b^{4} c^{4}\right )}{3465 \left (b x +a \right )^{\frac {11}{2}} \left (a^{5} d^{5}-5 a^{4} b c \,d^{4}+10 a^{3} b^{2} c^{2} d^{3}-10 a^{2} b^{3} c^{3} d^{2}+5 a \,b^{4} c^{4} d -b^{5} c^{5}\right )}\) | \(256\) |
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Leaf count of result is larger than twice the leaf count of optimal. 781 vs. \(2 (141) = 282\).
Time = 4.73 (sec) , antiderivative size = 781, normalized size of antiderivative = 4.57 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=-\frac {2 \, {\left (128 \, b^{4} d^{5} x^{5} + 315 \, b^{4} c^{5} - 1540 \, a b^{3} c^{4} d + 2970 \, a^{2} b^{2} c^{3} d^{2} - 2772 \, a^{3} b c^{2} d^{3} + 1155 \, a^{4} c d^{4} - 64 \, {\left (b^{4} c d^{4} - 11 \, a b^{3} d^{5}\right )} x^{4} + 16 \, {\left (3 \, b^{4} c^{2} d^{3} - 22 \, a b^{3} c d^{4} + 99 \, a^{2} b^{2} d^{5}\right )} x^{3} - 8 \, {\left (5 \, b^{4} c^{3} d^{2} - 33 \, a b^{3} c^{2} d^{3} + 99 \, a^{2} b^{2} c d^{4} - 231 \, a^{3} b d^{5}\right )} x^{2} + {\left (35 \, b^{4} c^{4} d - 220 \, a b^{3} c^{3} d^{2} + 594 \, a^{2} b^{2} c^{2} d^{3} - 924 \, a^{3} b c d^{4} + 1155 \, a^{4} d^{5}\right )} x\right )} \sqrt {b x + a} \sqrt {d x + c}}{3465 \, {\left (a^{6} b^{5} c^{5} - 5 \, a^{7} b^{4} c^{4} d + 10 \, a^{8} b^{3} c^{3} d^{2} - 10 \, a^{9} b^{2} c^{2} d^{3} + 5 \, a^{10} b c d^{4} - a^{11} d^{5} + {\left (b^{11} c^{5} - 5 \, a b^{10} c^{4} d + 10 \, a^{2} b^{9} c^{3} d^{2} - 10 \, a^{3} b^{8} c^{2} d^{3} + 5 \, a^{4} b^{7} c d^{4} - a^{5} b^{6} d^{5}\right )} x^{6} + 6 \, {\left (a b^{10} c^{5} - 5 \, a^{2} b^{9} c^{4} d + 10 \, a^{3} b^{8} c^{3} d^{2} - 10 \, a^{4} b^{7} c^{2} d^{3} + 5 \, a^{5} b^{6} c d^{4} - a^{6} b^{5} d^{5}\right )} x^{5} + 15 \, {\left (a^{2} b^{9} c^{5} - 5 \, a^{3} b^{8} c^{4} d + 10 \, a^{4} b^{7} c^{3} d^{2} - 10 \, a^{5} b^{6} c^{2} d^{3} + 5 \, a^{6} b^{5} c d^{4} - a^{7} b^{4} d^{5}\right )} x^{4} + 20 \, {\left (a^{3} b^{8} c^{5} - 5 \, a^{4} b^{7} c^{4} d + 10 \, a^{5} b^{6} c^{3} d^{2} - 10 \, a^{6} b^{5} c^{2} d^{3} + 5 \, a^{7} b^{4} c d^{4} - a^{8} b^{3} d^{5}\right )} x^{3} + 15 \, {\left (a^{4} b^{7} c^{5} - 5 \, a^{5} b^{6} c^{4} d + 10 \, a^{6} b^{5} c^{3} d^{2} - 10 \, a^{7} b^{4} c^{2} d^{3} + 5 \, a^{8} b^{3} c d^{4} - a^{9} b^{2} d^{5}\right )} x^{2} + 6 \, {\left (a^{5} b^{6} c^{5} - 5 \, a^{6} b^{5} c^{4} d + 10 \, a^{7} b^{4} c^{3} d^{2} - 10 \, a^{8} b^{3} c^{2} d^{3} + 5 \, a^{9} b^{2} c d^{4} - a^{10} b d^{5}\right )} x\right )}} \]
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\[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=\int \frac {\sqrt {c + d x}}{\left (a + b x\right )^{\frac {13}{2}}}\, dx \]
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Exception generated. \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=\text {Exception raised: ValueError} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1345 vs. \(2 (141) = 282\).
Time = 0.46 (sec) , antiderivative size = 1345, normalized size of antiderivative = 7.87 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=\text {Too large to display} \]
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Time = 1.39 (sec) , antiderivative size = 397, normalized size of antiderivative = 2.32 \[ \int \frac {\sqrt {c+d x}}{(a+b x)^{13/2}} \, dx=\frac {\sqrt {c+d\,x}\,\left (\frac {2310\,a^4\,c\,d^4-5544\,a^3\,b\,c^2\,d^3+5940\,a^2\,b^2\,c^3\,d^2-3080\,a\,b^3\,c^4\,d+630\,b^4\,c^5}{3465\,b^5\,{\left (a\,d-b\,c\right )}^5}+\frac {x\,\left (2310\,a^4\,d^5-1848\,a^3\,b\,c\,d^4+1188\,a^2\,b^2\,c^2\,d^3-440\,a\,b^3\,c^3\,d^2+70\,b^4\,c^4\,d\right )}{3465\,b^5\,{\left (a\,d-b\,c\right )}^5}+\frac {256\,d^5\,x^5}{3465\,b\,{\left (a\,d-b\,c\right )}^5}+\frac {16\,d^2\,x^2\,\left (231\,a^3\,d^3-99\,a^2\,b\,c\,d^2+33\,a\,b^2\,c^2\,d-5\,b^3\,c^3\right )}{3465\,b^4\,{\left (a\,d-b\,c\right )}^5}+\frac {128\,d^4\,x^4\,\left (11\,a\,d-b\,c\right )}{3465\,b^2\,{\left (a\,d-b\,c\right )}^5}+\frac {32\,d^3\,x^3\,\left (99\,a^2\,d^2-22\,a\,b\,c\,d+3\,b^2\,c^2\right )}{3465\,b^3\,{\left (a\,d-b\,c\right )}^5}\right )}{x^5\,\sqrt {a+b\,x}+\frac {a^5\,\sqrt {a+b\,x}}{b^5}+\frac {10\,a^2\,x^3\,\sqrt {a+b\,x}}{b^2}+\frac {10\,a^3\,x^2\,\sqrt {a+b\,x}}{b^3}+\frac {5\,a\,x^4\,\sqrt {a+b\,x}}{b}+\frac {5\,a^4\,x\,\sqrt {a+b\,x}}{b^4}} \]
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